函数的参数类型定义参数定义类型的方法 def person(name:str, age:int=33): print(name, age) 函数定义在python3.7之后可用 函数不会对参数类型进行验证 代码1234567891011121314151617181920212223# coding:utf-8def add(a: int, b: int = 3): print(a + b)add(1, 2)# add('hello', 'xiaomu')def test(a: int, b: int = 3, *args: int, **kwargs: str): print(a, b, args, kwargs)test(1, 2, 3, 4, name='小慕')def test2(a: int, b, c=3): print(a, b, c)test2(1, 3, 4)